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Domatic partitions with the property of Baire

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We show that 2ω cannot be partitioned into ω-many parts with the property of Baire, such that any x2ω is a universally bounded number of bit flips away from each of the ω-many parts. This shows that the axiom of choice (AC) is necessary for the infinite version of a folklore theorem on error correction.

Definitions

We will represent a graph G:(V,E) as the symmetrized ordered pairs of its edges. Thus GV2 and (x,y)G iff {x,y}E. A subset DV is a dominating set if for any xVD, there is some G-neighbor y of x with yD. Such D is a total dominating set if moreover the previous condition xD can be removed. A k-part (total) domatic partition of V is a k-part partition of V with each part a (total) dominating set.

In a more colorful language, a k-part domatic partition of V is a k-coloring of V such that every vertex xV sees every possible color in its G-neighbors and itself. Similarly, a k-part total domatic partition of V is a k-coloring of V such that every vertex xV sees every possible color in its neighbors.

We shall work in the Polish space 2ω with the usual topology. We use BP to mean the property of Baire. The equivalence relation E02ω×2ω is defined such that (x,y)E0 iff x(n)=y(n) for cofinitely many n<ω. We will no longer distinguish between E0 and its induced simple graph E0Δ2ω with Δ2ω={(x,x)}x2ω.

Background

The folklore theorm on error correction is as follows:

Theorem 1

Given n<ω, the hypercube graph on 2n admits an n-part total domatic partition iff n is a power of 2.

In the sense of the corresponding n-coloring, the n-regularity of the hypercube graph implies that every vertex sees every color in its neighbors exactly once.

For a two-part video explaining the above theorem, see [2] and [3].

The graphs E0, G0 and G1

We begin with an easy observation.

Theorem 2

The graph E0 admits an ω-part closed total domatic partition.

Proof

For n<ω, let Dn2ω contain all infinite binary strings of the form 0n1. Thus {Dn}n<ω form a family of ω-many disjoint clopen total dominating sets. The theorem holds as we expand this family into a full partition of 2ω.

This is the highest number of parts we can do, as E0 is ω-regular.

Typically in the study of graph coloring, one deals with a treeing G0 of E0. However as G0 does not have uniform vertex degree, it makes our analysis more difficult to continue. We shall instead consider the hypercube graph on 2ω, which can be seen as a homogenized version of G0.

Definition 1

Let G12ω×2ω be the graph such that (x,y)G1 iff x and y are exactly one bit flip away from each other. This is not a standard definition, and the need to emphasize on the 1 will come more apparent later.

Theorem 3

For any finite k<ω, the graph G1 admits a k-part clopen total domatic partition.

Moreover, under the assumption that “E0 has a transversal A2ω”, the graph G1 admits an ω-part total domatic partition.

Proof

The first part of the Theorem is essentially Theorem 1, where we leverage that 2ω with graph G1 can always be seen as the hypercube graph on 2n, but every element carries a tail of junk information.

For the second part, define ϕ:2ωω, such that for x2ω, if x0 is the unique element in A[x]E0, then ϕ(x) is the minimal n<ω such that for all mn, x(m)=x0(m). Next define π:ωω such that for every i<ω, π1{i}ω is infinite.

Note that for every x2ω and mϕ(x), if y is the result of flipping the m-th bit of x, then (x,y)G1 and ϕ(y)=m+1. Thus x has G1-neighbors of all sufficiently large ϕ(y). Consequently x has G1-neighbors of every possible πϕ(y)ω. Letting Di=(πϕ)1{i}, we see that {Di}i<ω is an ω-part total domatic partition of G1.

As a remark, any graph G on 2ω that contains G1 will share any domatic partition that G1 has, thus such G will always have a finite-part clopen total domatic partition. Finite-part domatic partitions will not continue to be of our main interest, but we'd like to mention without proof that the phenomenon of a finite-part clopen total domatic partition is already present at an intermediate phase between G0 and G1:

Theorem 4

Let σ:2<ωω be any function. Let the (ω-regular) graph Gσ on 2ω be defined where (x,y)Gσ iff there exists a prefix s2<ω such that sx,y, and x and y differ for a single bit flip at the location |s|+σ(s). Then for any k<ω, the graph Gσ admits a k-part clopen total domatic partition.

Moreover, E0 having a transversal implies that Gσ will admit an ω-part total domatic partition.

As to the infinte-part domatic partition of G1 from Theorem 3, the chaotic nature of a transversal A of E0 implies that the partition will have bad descriptive set theoretic properties. In fact there isn't any nice infinite-part domatic partition of G1, as we will see in the next section.

The graphs Gd

Definition 2

Given 1d<ω, define the graph Gd2ω×2ω such that (x,y)Gd iff x and y are at most d-many bit flips away. Thus Gd can be seen as a d-fold composition of G1 with itself.

We find that the graphs Gd form a hierarchy
G0G1G2G3E0
with their union nGn=E0. This is a process of thinning down the dominating sets of each graph as the graphs Gd become "thicker" with d, until 2ω is big enough to contain ω-many of them. Coincidentally, the partition {Dn}n<ω given in Theorem 2 is such that each Dn is a total dominating set for Gn+1. In terms of BP dominating sets, this is the best we can do:

Theorem 5

For any d<ω, the graph Gd does not admit any ω-part BP domatic partition.

Proof

We will demonstrate the idea behind the proof using the example of d=2, for the fear that the more general case will make notations too cumbersome.

The idea behind the proof is as follows. There is a relatively obvious reason for why Gd does not admit any infinite-part open domatic partition, which is that many vertices will witness the failure of such a domatic partition. In the BP case, there are still enough generic vertices to witness the failure of a domatic partition, in a very similar way.

Let {Dk}k<ω be an ω-part BP domatic partition of G2. For ij finite, let γi,j denote the automorphism of 2ω by flipping the two bits at locations i,j, and similarly define γi as the automorphism that flips the one bit at i. Note that every Dk is non-meager, as Dk and it countably many copies under γi and γi,j cover all of 2ω.

By localization, assume that D0 is comeager in some basic open Ns. Thus any γi or γi,j with i,j|s| will be an automorphism of Ns. The intersection of D0 with its copies under every such γi and γi,j will remain comeager in Ns, with the property that for any xNs in this intersection, any G2-neighbor of the form γi(x) or γi,j(x) with i,j|s| will remain in D0. Thus anytime this x sees a G2-neighbor that is not in D0, some <|s|-th bit of x must be flipped.

This leaves us with |s|-many cases. In particular, flipping any one bit of x will make x see at most |s|-many new colors, but x will need to see all ω-many colors, so a second bit must be flipped. If we can find some x such that it sees only finitely many new colors even after flipping two bits, then we are done as x is a witness of the failure of the domatic partition.

We will find sequential extensions (sn)n|s| of s as follows. Let s0=s. For every n<|s|, consider the basic open set Nγn(sn). As {Dk}k<ω partitions into it, there is some kn<ω such that Dkn is non-meager in Nγn(sn). By localization, there is some sn+1sn such that Dkn is comeager in Nγn(sn+1). By a similar discussion as before, for any generic xNγn(sn+1), the G1-neighbors of x will have only finitely many colors. Thus for any generic xNsn+1, the G1-neighbors of γn(x) will only have finitely many neighbors.

Thus as s|s| is a common extension of all sn, any x generic in Ns|s| will also be generic in every Nsn, and we fix such an x. Thus for any n<|s|, γn(x) has only finitely many G1-neighbors. Now γi,j(x) takes only one value when i,j|s|, and γi,j(x) takes on finitely many values when i<|s| or j<|s|. This x has the desired property of having only finitely many G2-neighboring colors, and we arrived at a contradiction.

For the general case of Gd, we expect some form of "inductions inside inductions", as we iterate through all cases of how some x gets connected to its Gd-neighbors. We still eventually stop after a finite amount of inductions, so the desired result holds.

Future work

There are certainly enough combinatoric space to play around with variations of the problem. Here are a few which weaken the notion of boundedness:

Question 1

Let {Dn}n<ω be a BP partition of 2ω, such that for some function Φ:ωω>0, every Dn is dominating for the graph GΦ(n). By Theorem 5 it follows that Φ is unbounded. Then does there exists some C>0, such that for cofinitely many n<ω, it holds that Φ(n)Clogn?

Question 2

For what type of function β:2ωω, does there exist a BP partition {Dn}n<ω of 2ω, such that every x2ω connects to every Dn via a Gβ(x)-edge?

Unexpectedly, the case of measure is not as straightforward as BP, due to not having the full localization theorem. Hence we can ask:

Question 3

Do the graphs Gd admit any infinite-part measurable domatic partition, with the usual coin-flipping probability measure on 2ω?

参考文献

投稿日:2021129
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duyaa
duyaa
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中国人です。今はAlexander Kechris先生の弟子として、カリフォルニア工科大学で博士課程を受けています。

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読み込み中...
読み込み中
  1. Definitions
  2. Background
  3. The graphs E0, G0 and G1
  4. The graphs Gd
  5. Future work
  6. 参考文献